`2(2x+y+5)+3(x-3y-1)=0` `2x-3y+1=0`

The locus of a point P ,so that the join of (-5,-1) and (3,2) subtend,a right angle at P is x^(2)+y^(2)+2x-3y-13=0 x^2+y^(2)+2x-3y-17=0 x^(2)+y^(2)+2x-y-17=0 x^(2)+y^(2)+4x-2y+1=0

The area of triangle formed by the lines 2x-y+1=0 , 3x-y+5=0 and 2x-5y+11=0

The area of the parallelogram formed by the lines 2x-3y+a=0, 3x-2y-a=0, 2x-3y+3a=0 and 3x-2y-2a=0 in square units , is

2x-y-5=0; x+3y-9=0

Let the equations of two planes be P_1: 2x-y+z=2 and P_2: x+2y-z=3 Equation of the plane which passes through the point (-1,3,2) and is perpendicular to each of the plane P_1 and P_2 is (A) x-3y-5z+20=0 (B) x+3y+5z-18=0 (C) x-3y-5z=0 (D) x+3y-5z=0

The lines x+y+z-3=0=2x-y+5z-6 and x-y-z+1=0=2x+3y+7 are coplanar then k equals

3x - 2y + 1 = 0 and 2x - y = 0 are the equation of the sides AB and AD of the parallelogram ABCD and the equation of a diagonal of the parallelogram is 5x - 3y - 1 = 0 . The equation of the other diagonal of the parallelogram is : (A) x-y+1=0 (B) x-y-1=0 (C) 3x+5y+13=0 (D) 3x+5y=13

2x-3y-3=0; (2x)/(3)+4y+(1)/(2)=0

Prove that the following lines are concurrent. (i)5x-3y=1 , 2x+3y=23 , 42x+21y=257 (ii) 2x+3y-4=0 , x-5y+7=0 , 6x-17y+24=0

If the lines x-y-1=0, 4x+3y=k and 2x-3y+1=0 are concurrent, then k is