A body starts with an initial velocity of 10ms-1 and is moving along a straight line with constant acceleration. When the velocity of the particle is 50ms- the acceleration is reversed in direction. The speed of the particle when it again reaches the starting point is

Average velocity of a particle moving in a straight line, with constant acceleration a and initial velocity u in first t seconds is.

A particle starts from the origin with a velocity of 10 m s^(-1) and moves with a constant acceleration till the velocity increases to 50 ms^(-1) . At that instant, the acceleration is suddenly reversed. What will be the velocity of the particle, when it returne to the starticng point?

A particle starts from rest at t=0 and moves in a straight line with an acceleration as shown below. The velocity of the particle at t=3 s is

A particle moves in a straight line with a uniform acceleration a. Initial velocity of the particle is zero. Find the average velocity of the particle in first 's' distance.

The velocity –position graph of a particle moving along a straight line is shown. Then acceleration of the particle at s = 15 m is :

A particle starting from rest moves along a straight line with constant acceleration for this velocity displacement graph will have the form-

If "v" is the velocity of a particle moving in a straight line and "a" is acceleration of the particle,then the speed of the particle would be decreasing if

A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes 20 m//s and in tenth second it travels a distance of 10 m . Then the acceleration of the particle will be.

A particle starts from rest and moves with constant acceleration. Then velocity displacement curve is: