A stone is projected vertically from the ground.It reaches the maximum height of 500m in 10 sec.After what time it will reach the ground from the maximum height reached?

A stone is thrown vertically up from the ground. It reaches a maximum height of 50 m in 10 sec. After what time it will reach the ground from maximum height position ?

A body is thrown vertically up from the ground. It reaches a maximum height of 100 m in 5 sec . After what time it will reach the ground from the maximum height position

A body is thrown vertically upwards from the ground. It reaches a maximum height of 20 m in 5s . After what time it will reach the ground from its maximum height position ?

A stone thrown vertically up from the ground reaches a maximum height of 50 m in 10s. Time taken by the stone to reach the ground from maximum height is

A stone projected vertically up from the ground reaches a height y in its path at t_(1) seconds and after further t_(2) seconds reaches the ground. The height y is equal to

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A stone projected vertically upwards from the ground reaches a maximum height h . When it is at a height (3h)//(4) , the ratio of its kinetic and potential energies is

When a body is projected vertically up from ground, its velocity is reduced to 1/3 rd of initial velocity at height 'y' above the ground. Then maximum height reached by the body is

A ball is projected vertically upward with speed of 50 m/s. Find a. the maximum height, b. the time to reach themaximum height, c. the speed at half the maximum height. Take g= 10 m/s^2 .

A stone is projected vertically upwards.When it reaches half the maximum height,its velocity is 20m/s.What is the maximum height attained by the stone? (g=10m/s^(2)