Body projected vertically upwards,crosses a point in `(t_(1))` further,`(t_(2))` seconds then velocity of projection ,is

A particle is projected vertically upward with velocity u from a point A , when it returns to the point of projection .

Two bodies are projected vertically upwards from one point with the same initial velocity v_0. The second body is projected t_0 s after the first. How long after will the bodies meet?

A body is projected vertically upward from the surface of the earth, then the velocity-time graph is:-

A body projected vertically upwords from the top of a tower reaches the ground in t_(1) second . If it projected vertically downwards from the some top with same velocity ,it reaches the ground in t_(2) seconds . If it is just dropped from the top it reaches the ground in t second .prove that t=sqrt(t_(1)t_(2))

A body projected vertically upwards from A, the top of a tower, reaches the ground in t_1 seconds.If it is projected vertically downwards from A with the same velocity, it reaches the ground in t_2 seconds.If it falls freely from rest at A, in what time does it reach the ground ?

A stone is projected vertically upwards. Its height h at time t sec is h=(80)t-(16)t^(2) . The velocity with which it hits the ground is

A body is projected verticallt upwards. If t_(1) and t_(2) be the times at which it is at a height h above the point of projection while ascending and descending respectively, then:

A ball projected from ground vertically upward is at same height at time t_(1) and t_(2) . The speed of projection of ball is [Neglect the effect of air resistance ]