A body is thrown with velocity `(4i+3j)` metre per second Its maximum height is `(g=10ms^(-2))`

[" A body is thrown with velocity "(4i+1)],[" 3j) metre per second.Its maximum "],[" height is "(g=10ms^(-2))],[" (A) "2.5m],[" (B) "0.8m],[" (C) "0.9m],[" (D) "0.45m]

If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10m//s)

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10sqrt2m//s . The maximum height attained by it is

A body is thrown vertically upwards and takes 5 seconds to reach maximum height. The distance travelled by the body will be same in :-

A body is projected with a velocity vecv =(3hati +4hatj) ms^(-1) The maximum height attained by the body is: (g=10 ms^(-2))

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body. (g=9.8m//s^(2))

Find the angle of projection for a projectile if its speed at maximum height is sqrt(5//9) times its speed at one-third of maximum height (g=10ms^(-2))

A body is thrown from the surface of the earth with velocity u m/s. The maximum height in metre above the surface of the earth up to which it will reach is (where, R = radish of earth, g=acceleration due to gravity)

A stone thrown vertically upwards takes 3 s to attain maximum height. Find the (i) initial velocity of the stone (ii) maximum height attained by the stone (g = 9.8 m s^(-2))

A body is thrown up with a kinetic energy of 10J. If it attains a maximum height of 5m, find the mass of the body.