A cell of internal resistance of 1 ohm and emf 5 volts balances on a potentiometer wire at length of 2 meter. The driving battery has emf of 50 volts. If the cell is shunted by 1 ohm resistance wire then find by what amount balance point will shift?

A cell of internal resistance 3 ohm and emf 10 volt is connected to a uniform wire of length 500 cm and resistance 3 ohm . The potential gradient in the wire is

In an experiment to find the internal resistance of a cell by a potentiometer, a balance was obtained for 50 cm length of the potentiometer wire, with a cell of e.m.f. 2V. When the cell was shunted by a resistance of 2 Omega , the balancing length of the potentiometer wire was 40 cm. What was the internal resistance of the cell ?

A battery of emf 26V and internal resistance 0.4 ohm is connected to a resistance of 10ohm and a potentiometer wire of length 10m. What is the potential gradient on the wire if the resistance of the potentiometer wire is 5 ohm –

is made of uniform material and cross-sectional area, and it has uniform resistance per unit length. The potential gradient depends upon the current in the wire. A potentiometer with a cell of emf 2 V and internal resistance 0.4 Omega is used across the wire AB . A standard cadmium cell of emf 1.02 V gives a balance point at 66 cm length of wire. The standard cell is then replaced by a cell of unknows emf e (internal resistance r ), and the balance. Point found similarly turns out to be 88 cm length of the wire. The length of potentiometer wire AB is 1 m . If the resistance is connected across the cell e , the balancing length will

A potentiometer wire has length 10m and resistance 10Omega . It is connected to battery of EMF 11 volt and internal resistance 1Omega , then the potential gradient in the wire is

A cell of emf (E) and internal resistance (r) is balanced across (l) length of potentiometer wire. If another cell of emf 2E and internal resistance (2r) is connected in parallel to the first cell , then the balancing length will be

A cell of emf E and internal resistance r connected in the secondary gets balanced against length l of potentiometer wire. If a resistance R is connected in parallel with the cell, then the new balancing length for the cell will be

In potentiometer experiment, a cell is balanced by length 120 cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is