`cos(sin^(-1)x)=(1)/(9)`

solve: cos(2sin^(-1)x)=(1)/(9)

If cos(2sin^(-1)x)=(1)/(9), then find the values of x.

If cos (2 sin^(-1) x) = (1)/(9) , then find the value of x

Let cos(2sin^(-1)x)=1/9xgt0 holds true for x=m/n , where m and n are co-prime further alpha and beta are root of quadratic eqation mx^2-nx-m+n=0,(alpha,beta) then point (alpha, beta) lies on the line

If sin^(-1)x in (0, (pi)/(2)) , then the value of tan((cos^(-1)(sin(cos^(-1)x))+sin^(-1)(cos(sin^(-1)x)))/(2)) is :

Prove that the identities,sin^(-1)cos(sin^(-1)x)+cos^(-1)sin(cos^(-1)x)=(pi)/(2)|x|<=1

cos(a sin ^(-1)"1/x)

Find the value of sin^(-1)(cos(sin^(-1)x))+cos^(-1)(sin(cos^(-1)x))