[" A body is projected up "],[" with a velocity 'u'.It "],[" reaches a point 'p' its path "],[" at times t "_(1)" and "t_(2)" seconds "],[" from the time of "],[" projection.Then "(t_(1)+t_(2))" is "]

A body is projected vertically upwards with some velocity u . It at the same point at t = 6 s as was at t = 4 s . Find the value of u .

A body is projected upwards with a velocity u . It passes through a certain point above the grond after t_(1) , Find the time after which the body posses thoruth the same point during the journey.

A stone projected vertically up from the ground reaches a height y in its path at t_(1) seconds and after further t_(2) seconds reaches the ground. The height y is equal to

For a given velocity, a projectile has the same range R for two angles of projection. If t_(1) and t_(2) are the time of flight in the two cases, then t_(1) = t_(2) is equal to

A particle is projected with speed u at angle theta with horizontal from ground . If it is at same height from ground at time t_(1) and t_(2) , then its average velocity in time interval t_(1) to t_(2) is

Trajectories of two projectiles are shown in figure.Let T_(1) and T_(2) be the time periods and u_(1) and u_(2) their speeds of projection.Then

Trajectories of two projectiles are shown in the figure. Let T_(1) and T_(2) be the time period and u_(1) & u_(2) speeds of projection. Then

A body is projected up with a speed u and the time taken by it is T to reach the maximum height H. Pich out the correct statement

A body is projected veritclaly upwards.The times corresponding to height h while ascending and while descending are t_(1) and t_(2) respectively. Then, the velocity of projection will be (take g as acceleration due to gravity)