Position of a particle,as a function of `t` is given by `e=5+4t+3t^(2)` ,find its rate of change ' x` with respect to t at t

A foce acts on a 30.g particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where x is in metre and t in second. The work done during the first 4s is

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

Position of a particle at any instant is given by x = 3t^(2)+1 , where x is in m and t in sec. Its average velocity in the time interval t = 2 sec to t = 3 sec will be :

The time dependence of the position of a particle of mass m = 2 is given by vec(r) (t) = 2t hat(i) - 3 t^(2) hat(j) Its angular momentum, with respect to the origin, at time t = 2 is :

The displacement s of a particle at a time t is given bys =t^(3)-4t^(2)-5t. Find its velocity and acceleration at t=2 .

The position of a particle along X-axis at time t is given by x=2+t-3t^(2) . The displacement and the distance travelled in the interval, t = 0 to t = 1 are respectively

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

Position of a particle moving along a straight line is given by x=2t^(2)+t . Find the velocity at t = 2 sec.