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Value of expression 5n^2 - 20n at n = 2 ...

Value of expression `5n^2 - 20n` at `n = 2` is:

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The expression 5^(2n) - 2^(3n) has a factor

For positive integer n_1,n_2 the value of the expression (1+i)^(n1) +(1+i^3)^(n1) (1+i^5)^(n2) (1+i^7)^(n_20), where i=sqrt-1, is a real number if and only if (a) n_1=n_2+1 (b) n_1=n_2-1 (c) n_1=n_2 (d) n_1 > 0, n_2 > 0

Knowledge Check

  • The value of n in the expression n^2 - 2(n!) + n = 0 for every n in N is :

    A
    a.6
    B
    b.1
    C
    c.3
    D
    d.data insufficient.

  • The value of n in the expression n^2-2(n!)+n = 0 for every n in N is :

    A
    6
    B
    1
    C
    3
    D
    both (b) and (c) are true

  • The expression n^(3) +3n^(2) + 5n +3, n in N is divisible by

    A
    3
    B
    4
    C
    5
    D
    6

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    Simplify the expression : 5m^(2)n^(2) - 3n^(2) + 6m^(2) - (9n^(2) + 2m^(2)n^(2)) and find its value when m = -2 and n = 4.

    Find the value of the expression (4^(n)+20^(m-1)xx12^(m-n)xx15^(m+n-2))/(16^(m)xx5^(2m+n)xx9^(m-1)) .

    For what values of m and n , the expression 2x^(2)-(m+n)x+2n is exactly divisible by (x-1) and (x-2) ?

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