The normal to `y^(2)=4a(x-a)` at the upper end of the latus rectum is

Show that the normals at the points (4a,4a)& at the upper end of the latus rectum of the parabola y^(2)=4ax intersect on the same parabola.

'O' is the vertex of the parabola y^(2)=4ax&L is the upper end of the latus rectum.If LH is drawn perpendicular to OL meeting OX in H, prove that the length of the double ordinate through H is 4a sqrt(5).

If the normals to the parabola y^(2)=4ax at the ends of the latus rectum meet the parabola at Q and Q', then QQ' is (a)10a(b)4a(c)20a(d)12a

The point of intersection of the normals to the parabola y^(2)=4x at the ends of its latus rectum is

‘O’ is the vertex of the parabola y^(2) = 4ax & L is the upper end of the latus rectum. If LH is drawn perpendicular to OL meeting OX in H, prove that the length of the double ordinate through H is 4asqrt5 .

Find the equations of normal to the parabola y^(2)=4ax at the ends of the latus rectum.

The triangle formed by the tangents to a parabola y^(2)=4ax at the ends of the latus rectum and the double ordinate through the focus is

Find the equation of a line joining the vertex of parabola y^(2)=8x to its upper end of latus rectum.

Angle between the parabolas y^(2)=4b(x-2a+b) and x^(2)+4a(y-2b-a)=0 at the common end of their latus rectum,is: