[" 2.5) A particle executing SHM,whose position time equation is given as "],[r=A cos(omega t+(pi)/(4))" ,its initial position is "]

A particle is executing SHM, whose equation is given below x=A cos (omegat+phi) . If t=0 , particle is mean position going towards positive x-direction then phi is equal to

A particle executing SHM is described by the displacement function x(t)=Acos(omegat+phi) , if the initial (t=0) position of the particle is 1 cm, its initial velocity is pii" cm "s^(-1) and its angular frequency is pis^(-1) , then the amplitude of its motion is

Acceleration of a particle, executing SHM, at it’s mean position is

A particle is executing SHM with time period T Starting from mean position, time taken by it to complete (5)/(8) oscillations is,

For a particle executing SHM , the kinetic energy (K) is given by K = K_(0)cos^(2) omegat . The equation for its displacement is

For a particle executing S.H.M., the kinetic energy K is given K = K_(0) cos ^(2)omega t . The maximum value of potential energy is:

The equation of a particle executing a linear S.H.M. is given by x=4 "cos" omega t + "sin" omega t . The "tan"gent of its initial phase angle is given by

A particle execute SHM and its position varies with time as x = A sin omega t . Its average speed during its motion from mean position to mid-point of mean and extreme position is

Find the amplitude and initial phase of a partical in SHM, whose motion equation is given as y = A sin omega t + B cos omega t

The displacement of a particle of mass 100 g executing SHm is given by the equation y = 0.2 cos (100t+(pi)/(4)) meter. Its total energy is