Let N=25723x5y ,where x and y are digits from 0 to 9 .If N is divisible by 12 then number of possible ordered pair (x,y) is :

If 2|x| - |y| = 3 and 4|x| + |y| = 3 , then number of possible ordered pairs of the form (x,y) is

A seven digit number made up of all distinct digits 8,7,6,4,2,x and y is divisible by 3. Then possible number of order pair (x,y) is

1x3y6 is a five digit number where x,y are digits and y exceeds x by 6.If this number is divisible by 18, then the value of (y)/(x) is:

A five-digit number XY235 is divisible by 3 where X and Y are digits satisfying X+Yle5 . What is the number of possible pairs of values of (X, Y) ?

xyz=24 , x,y,z in N. Then find the number of order pairs (x,y,z)

If 1,(x)/(2),y are in harmonic progression (x,y!=0), then the number of integral ordered pairs (X,Y) is

If Z=x^(2)-7x-9yi such that bar(Z)=y^(2)i+20i-12 then the number of order pair (x,y) is :