Verify that:- 18x [7+ (-3)] = [18x7] + [18x (-3)]

Prove that: 18x [7+ (-3)] = [18x7] + [18x (-3)]

18xx[7+(-3)]=[18xx7]+[18xx(-3)]

Verify the following: (a) 18xx[7+(-3)]=[18xx7]+[18xx(-3)](-21)xx[(-4)+(-6)]=[(-21)xx(-4)]+[(-21)xx(-6)]

(2x)/(3)=18

.Verify the following: 18times[7+(-3)],=[18times 7]+[18times(-3)]

If a=sin\ pi/18 sin\ (5pi)/18 sin\ (7pi)/18, and x is the solution of the equation y=2[x]+2 and y=3[x-2], where [x] denotes the integral part of x then a= (A) [x] (B) 1/[x] (C) 2[x] (D) [x]^2

Verify that 2 is a zero of the polynomial x^(3)+4x^(2)-3x-18.

Factorise the x ^(2) + 18x + 65

If 6x = 18, then 18x = 54

Divide 18x^(4) - 27 x^(3) + 6x by 3x.