Polynomial equation having roots `alpha,beta,gamma` is

If sum alpha=(2)/(3),sum alpha beta=(4)/(3) and alpha beta gamma=(8)/(3) then the equation whose roots are alpha,beta,gamma is

if alpha,beta,gamma are the roots of x^(3)-x^(2)+7x+2=0, then the equation whose roots are -alpha,-beta,-gamma is

If alpha is equal to beta, but alpha^(3)=19 alpha+1,beta^(3)=19 beta+1,gamma^(3)=19 gamma+1, then the equation whose roots are 1/ alpha,1/ beta,1/ gamma is

If alpha,beta,gamma are the roots of x^(3)+ax+b=0 then the transtormed equation having the roots (beta-gamma)^(2),(gamma-alpha)^(2),(alpha-beta)^(2) is obtained by taking x=

If alpha,beta,gamma are the roots of x^(3)+2x-3=0 then the transformed equation having the roots (alpha)/(beta)+(beta)/(alpha),(beta)/(gamma)+(gamma)/(beta),(gamma)/(alpha)+(alpha)/(gamma) is obtained by taking x=

If alpha, beta, gamma, are the roots of the equation x^(3)+3x-1=0, then equation whose roots are alpha^(2),beta^(2),gamma^(2) is

If alpha, beta, gamma and delta are the roots of the equation x ^(4) -bx -3 =0, then an equation whose roots are (alpha +beta+gamma)/(delta^(2)), (alpha +beta+delta)/(gamma^(2)), (alpha +delta+gamma)/(beta^(2)), and (delta +beta+gamma)/(alpha^(2)), is:

If alpha,beta,gamma are the roots of ax^(3)+bx^(2)+cx+d=0 and betaquad gammaquad alpha|=0,alpha!=beta!= then find the equation whose roots are alpha+beta-gamma,beta+gamma-alpha, and gamma+alpha-beta

If alpha,beta,gamma are the roots if the equation x^3-3x+11=0 then the equation whose roots are (alpha+beta),(beta+gamma),(gamma+alpha is