As velocity of the particle increases from zero and finally it decreases to zero hence acceleration is not remain positive for all the time of motion. Find out the average velocity of the motion V(m/s) 4 1/2 0 >t(sec) 1

The velocity of a particle is zero at time t = 2s, then

In S.H.M., the velocity of the particle at the mean position is 1 m/s and acceleration at the extremity is 2 m//s^(2) , the period of motion is

A particle moves in a straight line with a uniform acceleration a. Initial velocity of the particle is zero. Find the average velocity of the particle in first 's' distance.

The velocity-time graph of a particle moving along a straight line is shown is . The rate of acceleration and deceleration is constant and it is equal to 5 m s^(-2) . If the a average velocity during the motion is 20 m s^(-1) , Then . The value of t is.

A particle comes round a circle of radius 1 m once. The time taken by it is 10 sec . The average velocity of motion is

A particle starts from rest at t=0 and undergoes an acceleration as shown in figure. Draw the velocity-time graph of the motion of the particle during the interval from zero to 4 second.

Figure gives the x-t plot of a particle is one dimensional motion. Give the signs of position, velocity and acceleration of the particle at t = 0.3s