`sqrt(2)` , `root(3)(3)` , `root(4)(4)` Arrange in increasing order

root(3)(2) times root(3)(4)

The following are the steps involved in finding the least amont sqrt(3),root(3)(4) and root(6)(15) . Arrange them in sequential order. (A) therefore root(6)(15) is the smallest (B) therefore 3^(1//2)=3^(3//6), 4^(1//3)=4^(2//6), 15^(1//6)=15^(1//6) (C)The LCM fo the denominators of the exponents is 6 (D) sqrt(3)=3^(1//2), root(3)(4)=4^(1//3), root(6)(15)=15^(1//6) (E) therefore sqrt(3)=root(6)(27), root(3)(4)=root(6)(16)root(6)(15)=root(6)(15)

Multiply : root(3)(5) by root(4)(2) .

Arrange root(4)(3),root(3)(2)androot(6)(5) in the decreasing order.

If A = sqrt(2) , B = root(3)(3) and C = root(4)(4) then which of the relation is correct ?

root(5)(root(4)(3^2))

root (4) (root(3)(2^2))