`CH_(3)-CH=CH-CH_(2)C-=CH` In the above compounds the hybridization of `"1,3,5"` carbon atoms is

CH_(3)-CH=CH-CH_(2)C-=CH In the above compounds thehybridization of "1,3,5" carbon atoms is

In the hydrocarbon CH_(3)-CH = CH-CH_(2) -C = CH The state of hybridization of carbons 1,3 and 5 are in the following sequence

In the following molecule, the hybrid state of 1 and 3 carbon atoms is CH_2=C = CH_2

In the compound HC-=C-CH=CH_2 , the hybridizations of C-2 and C-3 carbons are, respectively,

The structural formula of a compound is CH_(3)-CH=C=CH_(2) . The type of hybridization at the four carbons from left to right are

In the compound HC-=C-overset(" "CH_(3))overset(|)(C)=CH_(2) , the hybridization of C_(2) and C_(3) carbons are respectively:

Evaluate the type of hybridization of carbon atoms marked with star. (A) overset**CH_(2)=CH-overset**undersetOunderset(||)C-O-H (B) CH_(3)-overset**CH_(2)-OH (C) CH_(3)-CH_(2)-overset**undersetOunderset(||)C-H (D) overset**CH_(3)-CH=CH-CH_(3) (E) CH_(3)-overset**C-=CH Number of carbon atoms of hybridization: Type-I =x ; Type-II=y; Type-III=z If "x" gt "y" gt "z" ; then find {[y^(2)-x+z]/6}