The potential energy of a projectile at maximum height is 3/4 times kinetic energy of projection.Its angle of projection

The potential energy of a projectile at its maximum height is equal to its kinetic energy there. If the velocity of projection is 20 m//s^(-1) ,its time of flight is (g=10 m//s^(2))

The kinetic energy of a projectile at the highest point is half of the initial kinetic energy. The angle of projection with the horizontal is

The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is .

Choose the correct option (i) The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is 60^(@) . (ii) A missile is fired for maximum range with an initial velocity of 20 m//s , the range of the missile is 40 m . (iii) A ball is projected with a kinetic energy E at an angle of 45^(@) to the horizontal. At the highest point during its flight, its kinetic energy will be E//2 . (iv) An object is projected at an angle of 45^(@) with horizontal. The horizontal range and the maximum height will be in the ratio 4:1

The horizontal range of a projectile is 2 sqrt(3) times its maximum height. Find the angle of projection.

The horizontal range of a projectile is 4 sqrt(3) times its maximum height. Its angle of projection will be

If the horizontal range of a projectile be a and the maximum height attained by it is b, then prove that the velocity of projection is

If the range of a projectile is x times its maximum height attained and also its speed at maximum height is 1/2 times its speed of projection, then the value of x is