Given A(6,0) and B(0,4) and 0 is the origin. If the locus P such that area of `trianglePOB=2` (area of `Delta POA`) is `x^(2)-ky^(2)=0` ,then k is equal to

" Given "A(6,0)" and "B(0,4)" and "O" is the origin.If the locus "P" such that area of "Delta POB=2" (area of "Delta POA" ) is "x^(2)-ky^(2)=0" ,then "k" is equal to "

O(0.0),A(6,0),B(0,4) are three points.P is a point such that area of Delta POB is twice the area of Delta POA ,if locus of P is x^(2)=my^(2) .then m is equal to

The coordinates of three points O, A, B are (0, 0), (0,4) and (6, 0) respectively. A point P moves so that the area of Delta POA is always twice the area of Delta POB . Find the equation to both parts of the locus of P.

Given the points A(0,4) and B(0,4). Then the equation of the locus of the point P(x,y) such that |AP-BP|=6, is

A(4,0) , B(-4,0) are two points.If the locus of P which moves such that |PA-PB|=6 is ax^(2)+by^(2)-63=0 .Then |a+b| is equal to

Let O be the origin and A, B be the two points having coordinates (0, 4) and (6, 0) respectively. If a point P moves in such a way that the area of the Delta OPA is always twice the area of Delta POB , then P lies on

Area of the triangle formed by the lines 2x-y=6 and 3x^(2)-4xy+y^(2)=0 is

A(0,0),B(1,2) are two points.If a point P moves such that te area of Delta PAB is 2sq . units then the locus of P is

Let two points be A(1,-1) and B(0,2) .If a point P(h,k) be such that the area of triangle PAB is 5 sq units and it lies on the line 3x+y-4 lambda =0 ,then the value of lambda is

If a+b=2h, then the area of the triangle formed by the lines ax^(2)+2hxy+by^(2)=0 and the line x-y+2=0, in sq.units is