`(3sqrt(2))/(sqrt(6)+sqrt(3))` rationalise

(3+sqrt(6))/(sqrt(3)+sqrt(2))

(1)/((sqrt(2)+sqrt(3))(sqrt(5)+sqrt(6))) in rationalised form is

Rationalise the denominator of (sqrt(6)+sqrt(3))/(sqrt(6)-sqrt(3)) and find its value of sqrt(2)=1.414

For (1)/(asqrt(x)+bsqrt(y)) the rationalising factor is a asqrt(x)-bsqrt(y) . If x=(7sqrt(3))/(sqrt(10)+sqrt(3))-(3sqrt(2))/(sqrt(15)+3sqrt(2))-(2sqrt(5))/(sqrt(6)+sqrt(5)) , then value of x^(4)+x^(2) is

(3sqrt(2))/(sqrt(6)-sqrt(3))+(2sqrt(3))/(sqrt(6)+2)-(4sqrt(3))/(sqrt(6)-sqrt(2))

(3sqrt(2))/(sqrt(6)-sqrt(3))-(4sqrt(3))/(sqrt(6)-sqrt(2))-(6)/(sqrt(8)-sqrt(12))=? a.sqrt(3)-sqrt(2)b*sqrt(3)+sqrt(2)c.5sqrt(3)d.1

Simplify : (3sqrt(2))/(sqrt(6)-sqrt(3))-(4sqrt(3))/(sqrt(6)-sqrt(2))+(2sqrt(3))/(sqrt(6)+2)

(2sqrt(6))/(sqrt(2)+sqrt(3))+(6sqrt(2))/(sqrt(6)+sqrt(3))-(8sqrt(3))/(sqrt(6)+sqrt(2))