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A vessel of "50L" contains "40g" of an i...

A vessel of "50L" contains "40g" of an ideal gas "X" at "600K" .The pressure exerted by the gas is 1 atm."20g" of an ideal gas "Y" is added to the same vessel keeping the same temperature.Total pressure becomes "3atm" .If the molar mass of "gas X" is "m (g/mol)" and the molar mass of gas "Y" is "n (g/mol)" then find the value of "(m+n)" .(Use "R=(1)/(12)(atmL)/(molK)" )

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