A body is droped from a height 122.5m.If its stopped after 3 seconds and again released the further time of descent is `(g=9.8m/s^(2))`

A body of mass 10 kg is dropped to the ground from a height of 10 metres. The work done by the gravitational force is (g=9.8m//sec^(2))

A body is dropped from rest from a height h. It covers a distance (9h)/(25) in the last seconds of fall. The height h is : (use g = 9.8 m//sec^(2) )

A stone is dropped from rest from the top of a tower 19.6m high. The distance travelled during the last second of its fall is (given g=9.8m//s^(2) ):

A body dropped from top of a tower falls through 40 m during the last two seconds of its fall. The height of tower in m is ( g= 10 m//s^@)

A stone is dropped from a certain heitht which can reach the ground in 5 s . It is stopped aftre 3 s of its fall and then it is again released. The total time taken by the stone to reach the ground will be .

If a body of mass 3 kg is droped from the top of a tower of height 25 metre, then its kinetic energy after 1 second will be (g = 10 m/s^(2))

A spherical body of mass "100g" is dropped from a height of "10m" from the ground.After hitting, the ground,the body rebounds to a height of "5m" .The impulse of force imparted by the ground to the body is given by : (given, g=9.8m"/"s^(2) )