`cot theta-tan theta=sin20^(@)+sin40^(@)-sin80^(@)" then "theta=`

Prove that : tan theta - cot theta = (2 sin^(2) theta - 1)/(sin theta cos theta)

Prove the following trigonometric identities: tan theta-cot theta=(2sin^(2)theta-1)/(sin theta cos theta)

(tan theta+cot theta)/(tan theta-cot theta)=2,(0<=theta<=90^(@)) then the value of sin theta is

(cos theta)/(sin(90^(@)+theta))+(sin(-theta))/(sin(180^(@)+theta))-(tan(90^(@)+theta))/(cot theta)

(sin^(2) 20^(@) + sin^(2) 70^(@))/(cos^(2) 20^(@) + cos^(2) 70^(@)) + [ (sin (90^(@) - theta).sin theta)/(tan theta) + (cos (90^(@) - theta).cos theta)/(cot theta) ] .

Prove that : (cos theta)/(1-tan theta)+(sin theta)/(1-cot theta)=sin theta+cos theta

y=1/((1+tan theta)^(sin theta-cos theta)+(cot theta)^(cos theta-cot theta))+ 1/((1+tan theta)^(cos theta-sin theta)+(cot theta)^(sin theta-cottheta)) +1/((1+tan theta)^(cos theta-cot theta)+(cot theta)^(cot theta-sin theta)) then (dy)/(dx) at theta=pi/3 is

If tan theta+cot theta=2 find sin theta

(1)/(csc theta-cot theta)-(1)/(sin theta)=(1)/(sin theta)-(1)/(csc theta+cot theta)

Prove that: (a) (sin 2 theta)/(1+cos 2 theta)=tan theta (b) (1+sin 2 theta+2theta)/(1+sin2 theta-cos 2 theta)=cot theta