The third term of `x^3 + 2x^2 + x + 1 = 0` is eliminated by putting `x= y + h.` The values of 'h' are

The transformed equation of x^(4)+4x^(3)+2x^(2)-4x-2=0 by eliminating second term is

In equation 8x+3y=11 , put y=3x-2 and find the values of x and y.

If x ^(2) - hx - 21 =0, x ^(2) - 3 hx + 35 =0 (h gt 0) has a common root, then the value of h is equal to

If (x-1)^2+(y-2)^2=0 , where x and y are integers, then the value of 2x+3y is :

The length of transverse common tangent of the circles x^2+y^2=1 and (x-h)^2+y^2=1 i s 2sqrt(3) , then the value of ' h ' is

If y=(x+(1)/(x)) , then the expression x^(4) +x^(3) -4x^(2) +x +1=0 can be simplified in terms of y as

Find the greatest and least value of y= x^(3)-3x^(2) + 6x-2 on [-1,1] y is differentiable function of x and y'(x) = 3x^(2) -6x + 6= 3(x^(2) -2x+2) =3(x-1)^(2) gt 0 .