.A ball is projected upwards from a height h above the surface of the earth with velocity v .The time at which the ball strikes the ground is

A body is projected vertically upward from the surface of the earth, then the velocity-time graph is:-

A body is projected vertically upward from the surface of the earth with escape velocity. Calculate the time in which it will be at a height (measured from the surface of the arth) 8 time the radius of the earth (R). Acceleration due to gravity on the surface of the earth is g.

A ball is thrown horizontally with a speed of 20 m//s from the top of a tower of height 100m velocity with which the ball strikes the ground is .

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

A ball is dropped from a height h above ground. Neglect the air resistance, its velocity (v) varies with its height (y) above the ground as :-

An objects is projected vertically upwards from the surface of the earth with a velocity 3 times the escape velocity v_(e ) from earth's surface. What will be its final velocity after escape from the earth's gravitational pull ?

An object is projected vertically upward from the surface of the earth of mass M with a velocity such that the maximum height reached is eight times the radius R of the earth. Calculate: (i) the initial speed of projection (ii) the speed at half the maximum height.

A ball is thrown straight upward with a speed v from a point h meter above the ground. The time taken for the ball to strike the ground is

A ball is thrown vertically upward with a velocity u from the top of a tower. If it strikes the ground with velocity 3u, the time taken by the ball to reach the ground is

If a ball is thrown upwards from the surface of earth :