If the time period t of a drop of liquid of density d, radius r, vibrating under surface tension s is given by the formula `t=sqrt((d^(a))r^(b)s^(c))` and if a=1 ,c=-1 then b is

If the time period t of the oscillation of a drop of liquid of density d, radius r, vibrating under surface tension s is given by the formula t=sqrt(t^(2b)s^(c)d^(a//2)) . It is observed that the time period is directly proportional to sqrt((d)/(s)). The value of b should therefore be:

Internal pressure inside a liquid drop of radius r and surface tension T is

If the period 'T' of a drop under surface tension 's' is given by T = sqrt(d^(a) r^(b) S^(c)) where d is the density , r is the radius of the drop. If a=1,c= -1 then the value of b is

The time of oscillation of a small drop of liquid under surface tension depends upon the density rho , radius r and surface tension S as : T prop rho^(a) S^(b) r^(c) find out a, b and c.

The excess pressure inside the drop of a liquid of surface tension T and radius of drom r is

Time period of an oscillating drop of radius r, density rho and surface tension S is t = K sqrt((rho r^3)/(S)) . Check the correctness of this relation

If the time period (T) of vibration of a liquid drop depends on surface tension (S) , radius ( r ) of the drop , and density ( rho ) of the liquid , then find the expression of T .

The time period (t) of vibration of a liquid drop depends on surface tension (s),radius ( r) of the drop and density (rho) of the liquid .Find t.

Time period of an oscillating drop of radius r, density rho and surface tension T is t=ksqrt((rhor^5)/T) . Check the correctness of the relation