if `sin A=(1)/(2)` and `cos B=(1)/(2)` then `A+B`=

Given that sin A=(1)/(2) and cos B=(1)/(2) ,then the value of (A+B) is

If sin(A-B)=(1)/(2) and cos(A+B)=(1)/(2) , 0^(@) lt (A+B) lt 90^(@) and A gt B then find A and B .

If 0

If 0

If A and B are positive acute angles such that sin (A - B) =1/2 and cos (A + B) = 1/2 , then A and B are given by

let a and b be real numbers such that sin a+sin b=(1)/(sqrt(2)) and cos+cos b=sqrt((3)/(2)) then

(sin A)/(sin B)=(1)/(3) and (cos A)/(cos B)=2 then the value of 32tan^(2)A= ...

If cos(A-B)=(1)/(2) and sin(A+B)=(1)/(2) find the smallest positive values of A and B

If sin(A-B)=(1)/(2),cos(A+B)=(1)/(2)0^(@) B, find A and B

If sin (A - B) = 1/2 and cos (A + B) = 1/2 where A > B > 0 and A + B is an acute angle, then the value B is