A boy projected up with some velocity crosses a point 'P' in its path in 4th second and 5th second. Height of point from ground is A) 49 m B) 196 m C) 88.2 m D) 98 m

A boy projected up with some velocity crosses a point ' P ' in its path in 4^th second and 5^ th second. Height of point from ground s

A boy projected up with some velocity crosses a point 'P' in its path in 4^ th second and 5^ th second. Height of point from ground is ( A) 49m B) 196m C) 88.2m D) 98m

A body projected with some velocity passes 2 points at the same height at the instant 2 seconds and 4 seconds. The maximum height reached by the body is (A) 44.1m (B) 24.1m (C) 22m (D) None

" A body projected with some velocity passes "2" points at the same height at the instant "2" seconds and "4" seconds.The maximum height reached by "

A body is projected up with a velocity u.It reaches a point 'p' its path at times t_(1) and t_(2) seconds from the time of projection.Then (t_(1)+t_(2))

A body is projected vertically upwards with velocity of 10m/s. At a point P in its path, its P.E. and K.E. are equal. What is the height of the point?

A body projected up reaches a point A in its path at the end of 4^( th) second and reaches the ground after 5 seconds from the start.The height of A above the ground is (g=10ms^(-2)) in m

A body moving with a uniform acceleration crosses a distance of 65 m in the 5 th second and 105 m in 9th second. How far will it go in 20 s?

A body projected up reached a point P of its path at the end of 4 seconds and the highest point at the end of 12 seconds. After how many seconds from the start will it reach P again ?

[" A body is projected up "],[" with a velocity 'u'.It "],[" reaches a point 'p' its path "],[" at times t "_(1)" and "t_(2)" seconds "],[" from the time of "],[" projection.Then "(t_(1)+t_(2))" is "]