`(sin4A)/(sin A)=K cos A cos2A` then `K`=

(sin A sin2A + sin3A sin6A + sin4A sin13A) / (sin A cos2A + sin3A cos6A + sin4A cos13A) = tan9A

If (2sin A)/(1+sin A-cos A)=k, then (1+sin A-cos A)/(1+sin A) is

if sin2A=2sin A cos A and sin20^(@)=K then the value of cos20^(@)cos40^(@)cos80^(@)cos160^(@)-

(cos3A-cos A)/(sin3A-sin A)+(cos2A-cos4A)/(sin4A-sin2A)=(sin A)/(cos2A cos3A)

If sin2A=2sinA cosAand sin20^(@)=K, " then the value of " cos20^(@)cos80^(@)cos160^(@) =__________.

If quad A+B-C=180^(@) and sin^(2)A+sin^(2)B-sin^(2)C=K sin A sin B cos C, then the value of K is

2^(sin x)+2^(cos x)>=K, then K=

(sin 2 kx)/(sin x)=2[cos x + cos 3 x + …+cos (2k -1)x] , then value of I=int_(0)^(pi//2)(sin 2 k x)/(sin x)cos x dx is :

Prove that: (cos 2A cos 3A -cos 2A cos 7A + cos A cos 10A)/("sin" 4A sin 3A - sin 2A sin 5A + sin 4A sin 7A) = cot 6A cot 5A

sin4A = 4sin A cos ^ (3) A-4cos A sin ^ (3) A