If `"(dy)/(dx)+(2y)/(x)=0`,y(1)=1" then `y(2)=(1)/(n')` "(n in N)"` .value of "n" is

((dy)/(dx))+((1)/(x))y=x^(n)

if x^(m)*y^(n)=1 then (dy)/(dx)

If ((x)/(a))^(n)+((y)/(b))^(n)=2 then ((dy)/(dx)) at (a,b) is

Find (dy)/(dx) , when: x^(n)+y^(n)=a^(n)

If y=a^(a^(x)) and (dy)/(dx)=y*a^(x)(log a)^(n) then the value of n is

If x^(2)y^(3)=(x+y)^(n+2) and (dy)/(dx)=y/x then n=

Let A_(n) be the area bounded by the curve y=x^(n)(n>=1) and the line x=0,y=0 and x=(1)/(2). If sum_(n=1)^(n)(2^(n)A_(n))/(n)=(1)/(3) then find the value of n .

If x^(3)=(x+y)^(n)*y^(2)" and "(dy)/(dx)=(y)/(x)," then: "n=

If x ^(n) y^(n) =( x+y ) ^(n),then (dy)/(dx)=