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Let A={x:(-2)/(5)<=x<=(pi-2)/(5)}and B={...

Let `A={x:(-2)/(5)<=x<=(pi-2)/(5)}`and `B={y:-1<=y<=1}` and `f:A rarr B` is defined by `f(x)=cos(5x+2)`. Then `f^(-1)(x)` is

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