A pendulum of length L carries a negative charge -q on the bob. A positive charge +q is held at the point of support. Then, the time period of the bob is

A bob of a simple pendulum of length l is negatively charged. A positively-charged metal plate is placed just below the bobt and the pendulum is made to oscillate. What will be the effect on the time period of the pendulum?

The bob of a perpendicular is positively charged.Another identical charge is placed at the point of suspension of the pendulum.The time period of pendulum

A simple pendulum of length l has a bob of mass m , with a charge q on it. A vertical sheet of charge , with the vertical . Its time period of oscillation is T in this position (i) tan theta = (sigma q)/(2 epsilon_(0) mg) (ii) tan theta = (sigma q)/(epsilon_(0) mg) (iii) T lt 2 pi sqrt((l)/(g)) (iv) T gt 2pi ((l)/(g))

Two equal negative charges are fixed at points and on y-axis. A positive charge Q is released from rest at the point on the x-axis. The charge Q will:

It takes 1 s for the bob to moves from one extreme position to other extreme postion. Then the time period of the pendulum is ______ s.

A simple pendulum of mass m and length L is held in horizontal position. If it is released from this position, then find the angular momentum of the bob about the point of suspension when it is vertically below the point of suspension.

A simple pendulum has time period T The bob is given negative charge and surface below it is given position change new time period will be

A simple pendulum of period T has a metal bob which is negatively charged. If it is allowed to oscillate above a positively charged metal plate, its period will