Particle moves from point A to point B along the line shown in figure under the action of force. `Vec F = - x hati + y hatj`. Determine the work done on the particle by `vec F` in moving the particle from point A to point B.

A body moves from a point A to B under the action of a force shown in figure. What is the amount of work done ?

A particle moves from a point (2m, 3m, 0) to (3 m, 2m, 0) under the action of force of magnitude 5N acting along the line y= x . The work done by the force on the particle during the displacement is

A particle moves from a point (2 m, 3 m, 0) to (3 m, 2 m, 0) under the action of force of magnitude 5 N acting along the line y = x. The work done by the force on the particle during the displacement is

A particle moves along Y - axis from y = 0 m under the influence of a force F = (9+3y+5y)^(2) N . Calculate the work done on the particle .

If vec(F) = y hat(i) + x hat(j) then find out the work done in moving the particle from position (2,3) to (5,6)

A particle has a displacement of vecs=hati+2hatj+hatk metre under the action of a force vec F =3hati -2hatj+5hatk . What is the work done ?

A particle constrained to move along the Y axis of a coordinate system in subject to a constant force . vec(F) = (5 hati + 4hatj + 3hatk) newton. What is the work done by this force is moving the particle throught 5 m along the Y axis ?

If vec(F)=yhati+xhatj then find out the work done in moving the particle from position (2, 3) to (5, 6)