`-log_8 log_4 log_2 16=`

If log_2 (log_3 (log_4 x))= 0, log_4 (log_3 (log_2 y))= 0 and log_3(log_4 (log_2z ))= 0, then the correct option is

the value of log_3 4 *log_4 5* log_5 6*log_6 7 * log_7 8*log_8 9

find the value of log_(2)log_(2)log_(2)16=

Prove that (i) log_(2)log_(2)log_(2)16=1

Evaluate log_2 log_2 16

Solve : log_4 8+ log_4(x+3)-log_4(x-1)=2

difference between log _(3)log_(2)log_(sqrt(5))625 and log_(2)log_(2)log_(2)16

log_ (4) 2-log_ (8) 2+log_ (16) 2 -.... oo

The sum of the series "log"_(4)2-"log"_(8)2 + "log"_(16)2- "log"_(32) 2+…., is

Comprehension 2 In comparison of two numbers, logarithm of smaller number is smaller, if base of the logarithm is greater than one. Logarithm of smaller number is larger, if base of logarithm is in between zero and one. For example log_2 4 is smaller than (log)_2 8 a n d(log)_(1/2)4 is larger than (log)_(1/2)8. Identify the correct order: (log)_2 6 (log)_3 8> log_3 6>(log)_4 6 (log)_3 8>(log)_2 6> log_3 6>(log)_4 6 (log)_2 8<(log)_4 6