`2 mu C` charge is shifted from "P" to "Q" .If workdone by external force in this process is `160times10^(-6)` joule,then potential difference between points "P" and "Q" i.e.`V_(P)-V_(Q)` is

The potential difference between the points P and Q in the adjoining circuit will be-

Potential difference between the points P and Q in the electric circuit shown is

1 mu C charge is shifted from A to B, and it is found that work done by an external force is 40 mu J . In doing so against electrostatic forces, find potential difference V_A - V_B .

A charge of magnitude 10^(-6) C is placed at the origin. There are two points P(sqrt3, sqrt3) and Q(sqrt6,0) . Find potential difference between point P & Q.

Figure shows two rings having charges Q and - sqrt(5)Q . Find potential difference a and B i.e. (V_(A)-V_(B)) .

In the circuit as shown,the charge varies with time t as q=t^(3)-4 ,where q is in coulombs and t is in seconds.Where at t=2 , the potential difference between A and B, V_(A)-V_(B) in volts is

If in the circuit shown below, the internal resistance of the battery is 1Omega and V_(P) and V_(Q) are the potentials at P and Q respectively, the potential difference between te point P and Q is

In the given network if potential difference between p and q is 2V and C_(2)=3C_(1) , find the potential difference between a & b .

Two point charge q_(1) = -10xx10^(-6) C " and "q_(2)=15xx10^(-6) are 40 cm apart as shown in figure. Find the potential difference between the point P and Q.

In Figure if the potential at Point P is 100 V , what is the potential at point Q?