If the perpendicular bisector of the line segment joining `A(alpha,3)` and B(2,-1) has y-intercept 1 then `| alpha|`=

Statement - 1 : If the perpendicular bisector of the line segment joining points A (a,3) and B( 1,4) has y-intercept -4 , then a = pm 4 . Statement- 2 : Locus of a point equidistant from two given points is the perpendicular bisector of the line joining the given points .

The perpendicular bisector of the line segment joining A(1, 4) and B(t, 3) has y - intercept equal to -4 . Then, the product of all possible values of t is equal to

The equation of the perpendicular bisector of the line segment joining A(2,-3) and B(-6,5) is

The equation of the perpendicular bisector of the line segment joining A(-2, 3) and B(6,5) is

The perpendicular bisector of the line segment joining P(1,4) and Q(k,3) has y -intercept equal to -4 .Then a possible value of -k is

The perpendicular bisector of the line segment joining P(1,4) and Q(k,3) has y-intercept -4. Then a possible value of k is (1)1(2)2(3)-2(4)-4

The perpendicular bisector of the line segment joining P(1,4) and Q(K,3) has Y intercept -4 then a possible value of K is

The perpendicular bisector ofthe line segment joining P(1,4) and Q(K,3) has Y intercept -4 then a possible value of K is (1)-4(2)1(3)2 (4) -2

The perpendicular bisector of the line segment joining the points A(1,5) and B(4,6) cuts the Y-axis at