`lim_(n->oo) co sx/2*co sx/4*co sx/8......co sx/(2^n)`

Evaluate lim_(n rarr oo){cos((x)/(2))cos((x)/(4))cos((x)/(8))...cos((x)/(2^(n)))}

cos A cos2A cos4A......cos2^(n-1)A

If lim_(x rarr0)(1-cos x*cos2x*cos3x...cos nx)/(x^(2)) has the value equal to 263, find the value of n ( where n in N)

The value of lim_(nrarroo)(cos.(x)/(2)cos.(x)/(4)cos.(x)/(8)………cos.(x)/(2^(n+1))) is equal to

The value of lim_(nrarroo)(cos x cos .(x)/(2)cos.(x)/(4)..cos .(x)/(2^(n))) is equal to

We have f (x) lim_(n to oo) cos (x)/(2) cos (x)/(2^(2)) cos (x)/(2^(3)) cos (x)/(2^(4)) …… …. cos (x)/(2^(n)) = ("sin" x)/(2^(n) "sin" (x)/(2^(n))) using the identity lim_(n to oo) lim_(x to 0) f(x) equals

lim_(n->oo)(cosx+cos3x+cos5x+cos(2n-1)x)/n where x!=kpi, k in I