" (f) `(5^(6)times a^(7))/(5^(2)times a^(3)times(10)^(0))`

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

(3^(-5)times10^(-5)times125)/(5^(-7)times6^(-5))

3^(-5)times10^(-4)times(5^(4))/(5^(2))times6^(-5)=

Evaluate : ((6)/(7))^(2)times((6)/(5))^(-3)times((7)/(5))^(2)

-(2)/(3)times(3)/(5)+(5)/(2)-(3)/(5)times(7)/(6)

Simplify -(2)/(3)times5(1)/(2)times2times7(5)/(6)times(9)/(11)

Evaluate : (5/7)^3 times ( 5/7 )^(-6) times ( 1/3 )^(-2 ) times ( 3/5 )^-2

((5)/(6))times((-2)/(5)+(3)/(10))