`(3x)/2-(5y)/3=-2`, `x/3+y/2=13/6`

Solve the following pair of linear equations by the substitution method. (i) x+y=14 ;x- y=4 (ii) s-t=3; s/3+t/2=6 (iii) 3x-y=3;9x-3y=9 (iv) 0. 2 x+0. 3 y=1. 3 ;0. 4 x+0. 5 y=2. 3 (v) sqrt(2)x+sqrt(3)y=0;sqrt(3)x-sqrt(8)y=0 (vi)3x/2-5y/2=-2;x/3+y/2=13/6

Let equation of two sides of a triangle are 4x+5y=20 and 3x-2y+6=0 If orthocentre of triangle is (1,1) then the equation of third side of triangle is (a) y+10=(-13)/61(x+35/2) (2) y+10=(-13)/61(x-35/2) (3) y+10=13/61(x-35/2) (4) y-10=13/61(x-35/2)

4x-2y=3 6x-3y=5

Solve :(x+y)/(x-y)=(3)/(2),3x-2y=13

2x+5y=8/3, 3x-2y=5/6

Solve for x and y:(2x+1)/(7)+(5y-3)/(3)=12(3x+2)/(2)-(4y+3)/(9)=13