If `sectheta=x+1/(4x),` then `s e ctheta+t a ntheta=` `x ,1/x` (b) `2x ,1/(2x)` (c) `-2x ,1/(2x)` (d) `-1/x ,x`

If sec theta=x+(1)/(4x), then sec theta+tan theta=x,(1)/(x) (b) 2x,(1)/(2x)(c)-2x,(1)/(2x)(d)-(1)/(x),x

If sec theta= x+1/(4x) then sec theta+ tan theta= a, x, 1/(x), b. 2x, 1/(2x), c.-2x, 1/(2x), d.-1/x, x

If sectheta=x+(1)/(4x) ,prove that sectheta+tantheta=2xor(1)/(2x)*

If tan theta=x-(1)/(4x), then sec theta-tan theta is equal to -2x,(1)/(2x) b.(1)/(2x),2x c.2x d.2x,(1)/(2x)

If sec theta+tan theta=x, then sec theta=(a)(x^(2)+1)/(x) (b) (x^(2)+1)/(2x)(c)(x^(2)-1)/(2x) (d) (x^(2)-1)/(x)

If sec theta+tan theta=x, then tan theta=(x^(2)+1)/(x) (b) (x^(2)-1)/(x)( c) (x^(2)+1)/(2x) (d) (x^(2)-1)/(2x)

(2x + 1) / (x) + (4x) / (2x + 1) = 5

If 2tan^(-1)x+sin^(-1)((2x)/(1+x^2)) is independent of ' x ' then (a)x in (-1,1) (b) x in (-oo,-1) (c)x in [1,oo) (d) x in (0,1)

If f(x)=(2x+1)/(2x^(3)+3x^(2)+x) and S={x:f(x)>0} then s contains (a) (-oo,-(3)/(2))(b)(-(3)/(2),-(1)/(4))(c)(-(1)/(4),(1)/(2)) (d) ((1)/(2),3)

The greatest 'x' satisfying the inequation (2x+1)/(3)-(3x-1)/(2)>1 is: -4 (b) 4(c)1(d)-1