The perimeter of a triangle is 20 and the points (-2, -3) and (-2,3) are two of the vertices of it. Then the locus of third vertex is : (x-2), y = 49 40 (x+2) y? = 1 49 40 (x+2)? y? 1 40 49 (x-2) y = 40 49

The area of a triangle is 5. Two of its vertices are (2,1) and (3,-2). The third vertex lies on y=x+3. Find the third vertex.

The area of a triangle is 5. Two of its vertices are (2,1) and (3,-2). The third vertex lies on y=x+3. Find the third vertex.

The area of a triangle is 5. Two of its vertices are (2, 1) and (3, - 2). The third vertex is (x, y) where y = x + 3. Then the co-ordinate of the third vertex is

the length of the latusrectum of the ellipse (x^(2))/(36)+(y^(2))/(49)=1 , is

A tangent of slope 2 to the ellipse (x^(2))/(36)+(y^(2))/(49)=1 has an intercept on the y-axis of length

Let A(2,-3) and B(-2,1) be vertices of a triangle ABC. If the centroid of this triangle moves on the line 2x+3y=1, then the locus of the vertex C is the line 2x+3y=92x-3y=73x+2y=53x-2y=3

IfA(2,-3) and B(-2, 1) are two vertices of a triangle and third vertex moves on the line 2x +3y 9,th the locus of the centroid of the triangle is 21. AIEEE-2011 (1) x-y=1 (2) 2x + 3y = 1 (3) 2x + 3y = 3 (4) 2x-3y = 1