`4(2a-3b)^(2)+8(2a-3b)`

Factorize: (i) 6(2a+3b)^(2)-8(2a+3b)

Factorize: 4(x+y)^(2)-28y(x+y)+49y^(2)(2a+3b)^(2)+2(2a+3b)(2a-3b)+(2a-3b)^(2)

-3 (a + b) + 4 (2a - 3b) - (2a - b)

Simplify each of the following: -5(a+b)+2(2a-b)+4a-7 -3(a+b)+4(2a-3b)-(2a-b)

factorize ( i ) 4(a+b)-6(a+b)^(2) (ii) 8(3a-2b)^(2)-10(3a-2b)

The factors of 8a^(3)+b^(3)-6ab+1 are (a) (2a+b-1)(4a^(2)+b^(2)+1-3ab-2a) (b) (2a-b+1)(4a^(2)+b^(2)-4ab+1-2a+b)(2a+b+1)(4a^(2)+b^(2)+1-2ab-b-2a) (d) (2a-1+b)(4a^(2)+1-4a-b-2ab)

Simplify: 4ab(a-b)-6a^(2)(b-b^(2))-3b^(2)(2a^(2)-a)+2ab(b-a)

8(3a-2b)^2-10(3a-2b)

If a^2+b^2+2b + 4a + 5=0 , then the value of (2a-3b)/(2a+3b) is equal to: यदि a^2+b^2+2a + 4a + 5=0 , (2a-3b)/(2a+3b) का मान ज्ञात करें :

if (2a+3b+4c+5d)/(2a-3b-4c-5d)=(2a-3b+4c-5d)/(2a-3b-4c+5d) , then show that a,3b,2c and 5d are in proportion.