The rate law of a chemical reaction give...

The rate law of a chemical reaction given below:
`2NO+O_(2)rarr 2NO_(2)`
is given as rate `=K[NO]^(2)[O_(2)]`. How will the rate of reaction change if the volume of reaction vessel is reduced to `1//4th` of its original valur?

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The rate law of a chemical reaction given below: `2NO+O_(2)rarr 2NO_(2)` is given as rate `=K[NO]^(2)[O_(2)]`. How will the rate of reaction change if the volume of reaction vessel is reduced to `1//4th` of its original valur?

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The rate law of a chemical reaction given below:
`2NO+O_(2)rarr 2NO_(2)`
is given as rate `=K[NO]^(2)[O_(2)]`. How will the rate of reaction change if the volume of reaction vessel is reduced to `1//4th` of its original valur?