In adjoining figure,`AP _|_ BC` , `AD || BC` ,then find `Ar.(Delta ABC)``:``Ar.(Delta BCD)`Fig.

In the adjoining figure, AP ⊥ BC ,AD||BC ,then find A(Delta ABC):A(Delta BCD) .

In the given figure DE||BC and AD:DB =5:4 Find the ratio ar (Delta DEF) : ar (Delta CFB)

In the adjoining figure,E is a point on the median AD of a Delta ABC. Show that ar (Delta ABE)=(Delta ACE)

In the given figure, AP ||BQ ||CR . Prove that ar(Delta AQC) = ar (DeltaPBR)

In Figure 1,PQ|BC and AP:PB=1:2* find the ratio of (ar Delta APQ)/(ar Delta ABC)

In given figure. If area of parallelogram ABCD is 30 cm^(2) then find ar (Delta ADE) +" ar "(Delta BCE)

In figure, if DE abs() BC, then find the ratio of ar ( DeltaADE ) and ar(DECB).

In the adjoning figure, D and E are the points on the sides AB and AC respectively of Delta ABC and area of Delta BCE = " area of " Delta BCD . Prove that DE ||BC

In figure, if ar( Delta ABC) = 28 cm^(2) , then find ar( I I^(gm) AEDF).