`K_(b)` and `K_(f)` for water are respectively `0.52` and `1.86kg` `mol^(-1)` respectively.For an aqueous glycolic solution freezing point is `-3.72^(0)C` .What is the boiling point of the solution?

For an aqueous solution freezing point is -0.186^(@)C . The boiling point of the same solution is (K_(f) = 1.86^(@)mol^(-1)kg) and (K_(b) = 0.512 mol^(-1) kg)

Some ethylene glycol HOCH_(2)CH_(2)OH is added to your car cooling system along with 5 kg of water .If the freezing point of water glycol solution is -15.0^(@)C what is the boiling point of the solution ? (k_(b)=0.52 kg mol^(-1) and k_(f)=1.86 k kg mol^(-1) for water)

A 0.1 molal aqueous solution of a weak acid is 30% ionized. If K_(f) for water is 1.86^(@)C//m , the freezing point of the solution will be.

An aqueous solution freezes at -0.186^(@)C (K_(f)=1.86^(@) , K_(b)=0.512^(@) . What is the elevation in boiling point?

An aqueous solution freezes on 0.36^@C K_f and K_b for water are 1.8 and 0.52 k kg mol^-1 respectively then value of boiling point of solution as 1 atm pressure is