`[(1)/(1times2)+(1)/(2times3)+(1)/(3times4)+......+(1)/(99times100)]` =

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lim_(x->oo) [(1)/(1times2)+(1)/(2times3)+(1)/(3times4)+.....+(1)/(n(n+1))]

3^(-1)times2^(-1)times6=

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(5)/(4)times(2)/(6)+(3)/(2)times(2)/(1)+(3)/(6)times(3)/(2)

[(1)/(4)+(1times3)/(4times8)+(1times3times5)/(4times8times12)]=

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1 times 2+2 times 3+3 times 4+....=?

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Evaluate: 1/3 times 1/4 times 1/3 times 1/3