If `f:R rarr R,g:R rarr R` are defined by `f(x)=3x-4` and `g(x)=2+3x` ,then `(g^(-1) of^(-1))(5)=`

If f:R rarr R and g:R rarr R are define by f(x)=3x-4 and g(x)=2+3x , then (g^(-1)of^(-1))(5)=

f:R rarr Rf:R rarr R is defined by f(x)=x^(2)-3x+2 find

If f:R rarr R and g:R rarr R are defined by f(x)=x-[x] and g(x)=[x] is x in R then f{g(x)}

Let f:R rarr R , g : R rarr R be two function given by f(x) =5x-4 and g(x) = x^(3)+7 then (fog)^(-1) (x) equals

If f:R rarr R and g:R rarr R given by f(x)=x-5 and g(x)=x^(2)-1, Find fog

Let f:R rarr R and g:R rarr R be defined by f(x)=x+1 and g(x)=x-1. Show that fog =gof=I_(R)

Let f:R rarr and g:R rarr R be defined by f(x)=x+1 and g(x)=x-1. Show that fog =gof=I_(R) .

Let f:R rarr R and g:R rarr R be defined by f(x)=x^(2) and g(x)=x+1. Show that fog != gof

If the function f:R rarr R , g:R rarr R defined by f(x)=3x-1 , g(x)=x^(2)+1 then find i) (fof)(x^(2)+1) ii) (fog )(2)