`sin theta . Cosec theta` = ?

If sintheta + cosec theta = 2, then find th value of sin^(n)theta + cosec^(n)theta, where is any real number.

If sintheta + cosectheta = 2 then sin^6theta + cosec^6theta is..

If sintheta + cosectheta = 2 then sin^6theta + cosec^6theta is..

If cos theta + sin theta = m , sec theta + cosec theta =n , What is m//n ?

If sin theta=4/5, cosec theta=?

Prove that: (sin theta)/(cot theta + "cosec"theta) = 2 + (sin theta)/(cot theta - "cosec"theta)

Evaluate : sin theta cos theta - (sin theta cos (90^(@) - theta) cos theta)/( sec (90^(@) - theta)) - (cos theta sin (90^(@) - theta) sin theta)/( cosec (90^(@) - theta))

Prove each of the following identities : (sin theta)/((cot theta + "cosec" theta )) - (sin theta)/((cot theta - "cosec" theta))= 2