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Triangles A B C and +DBC are on the same...

Triangles `A B C` and +DBC are on the same base `B C` with A, D on opposite side of line `B C ,` such that `a r(triangle ABC)=ar( triangleDBC)dot` Show that `B C` bisects `A Ddot`

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`ar(/_\ABC)=ar(/_\DBC)`
`1/2xxBCxxAE=1/2xxBCxxDF`
`AE=DF->"eq(1)"`
`"In "/_\AEO and /_\DFO`
`AE=DF`
`/_AEO=/_DFO->"(eq (1) )"`
`/_AOE=/_DOF->"("90^0" each)"`
`by "AAS axion"`
...
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